3x^2+x=44

Solution for 3x^2+x=44 equation:

3x^2+x=44

We move all terms to the left:

3x^2+x-(44)=0

a = 3; b = 1; c = -44;
Δ = b2-4ac
Δ = 12-4·3·(-44)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-23}{2*3}=\frac{-24}{6}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+23}{2*3}=\frac{22}{6}
=3+2/3
$